Differentialrechnung
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|<math>\begin{cases}\operatorname{artanh}x+C=\frac 1 2 \ln\frac{1+x}{1-x}+C,& |x|<1\\\operatorname{arcoth}x+C=\frac 1 2 \ln\frac{x+1}{x-1}+C,& |x|>1\end{cases}</math> | |<math>\begin{cases}\operatorname{artanh}x+C=\frac 1 2 \ln\frac{1+x}{1-x}+C,& |x|<1\\\operatorname{arcoth}x+C=\frac 1 2 \ln\frac{x+1}{x-1}+C,& |x|>1\end{cases}</math> | ||
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- | |<math></math> | + | |<math>\frac 1{a^2+x^2}</math> |
- | |<math></math> | + | |<math>\frac 1 a \arctan\frac x a+C</math> |
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- | |<math></math> | + | |<math>\frac 1{a^2-x^2}</math> |
- | |<math></math> | + | |<math>\begin{cases}\frac 1 a \operatorname{artanh}\frac x a + C,& |x|<a\\\frac 1{2a}\ln\frac {a-x}{a+x} + C,& |x|>a\end{cases}</math> |
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- | |<math></math> | + | |<math>\frac 1{x^2-a^2}</math> |
- | |<math></math> | + | |<math>\begin{cases}-\frac 1 a \operatorname{arcoth}\frac x a + C,& |x|>a\\\frac 1{2a}\ln\frac {x-a}{x+a} + C,& |x|<a\end{cases}</math> |
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|<math></math> | |<math></math> |
Revision as of 08:38, 17 September 2008
Funktion | Ableitung | Integral |
weitere Integrale
Funktion | Integral |